z^2+2iz=1+i

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Solution for z^2+2iz=1+i equation:


Simplifying
z2 + 2iz = 1 + i

Reorder the terms:
2iz + z2 = 1 + i

Solving
2iz + z2 = 1 + i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1i' to each side of the equation.
2iz + -1i + z2 = 1 + i + -1i

Reorder the terms:
-1i + 2iz + z2 = 1 + i + -1i

Combine like terms: i + -1i = 0
-1i + 2iz + z2 = 1 + 0
-1i + 2iz + z2 = 1

Add '-1z2' to each side of the equation.
-1i + 2iz + z2 + -1z2 = 1 + -1z2

Combine like terms: z2 + -1z2 = 0
-1i + 2iz + 0 = 1 + -1z2
-1i + 2iz = 1 + -1z2

Reorder the terms:
-1 + -1i + 2iz + z2 = 1 + -1z2 + -1 + z2

Reorder the terms:
-1 + -1i + 2iz + z2 = 1 + -1 + -1z2 + z2

Combine like terms: 1 + -1 = 0
-1 + -1i + 2iz + z2 = 0 + -1z2 + z2
-1 + -1i + 2iz + z2 = -1z2 + z2

Combine like terms: -1z2 + z2 = 0
-1 + -1i + 2iz + z2 = 0

The solution to this equation could not be determined.

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